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§@ªÌDavidoff-Lite

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§@ªÌn_akemi

A¡Ò(10) = A¡Ò(2¡Ñ5) ¥i¥H¼g¦¨ A/(2¡Ñ5)
¦ý¬O¹ê»Ú¤W¥iµø¬° A¡Ñ[1/(2¡Ñ5)] = A¡Ñ(1/2)¡Ñ(1/5)
­Y±N¨ä¤¤5 §ï¬° ÅܼÆY «h¡AA¡Ò(2¡ÑY) = A/(2¡ÑY) ­¼¸¹¬Ù²¤«á±o A/(2Y)
¦P²z A¡Ò(2Y) À³¬° A/(2Y) = A¡Ñ(1/2)¡Ñ(1/Y) ¤£µ¥©ó A/2Y

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¥ç§YA/2Y ­Yµ¥©ó A/2¡ÑY = (A/2)¡ÑY = AY/2 = YA¡Ò2
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©Ò¥H¡A¥N¦^­ìÃD30¡Ò2(2+3)À³¬°30/(2(2+3))

§@ªÌn_akemi

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4+6 = (4+6) = (2(2+3)) = 2(2+3)
30¡Ò(4+6) = 30¡Ò(2(2+3)) = 30¡Ò2(2+3)

§@ªÌlowyield

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http://en.wikipedia.org/wiki/Order_of_operations
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Similarly, care must be exercised when using the slash ('/') symbol. The string of characters "1/2x" is interpreted by the above conventions as (1/2)x. The contrary interpretation should be written explicitly as 1/(2x). Again, the use of brackets will clarify the meaning and should be used if there is any chance of misinterpretation.
§Ú·Q³o¤]¬O¬°¦ócasio & TI ·|§â­ì¥»ªº1/2Xµ¥©ó1/(2X)­×§ï¬°1/2Xµ¥©ó(1/2)Xªº­ì¦]§a?À³¸Ó´N¬O³oºØ°ÝÃD³y¦¨¤Ó¦h¤H§xÂZ¤F!
§Ú¤â¤W¨S¼Æ¾Ç®Ñ¥i¥H¬d,¤£¹LGOOGLE 1/2X, SIN(1/2X), 1/2PI¤§Ãþªº¤èµ{¦¡...À³¸Óº¡¦hÃþ¦ü°ÝÃDªº!

§@ªÌAdsmt

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An expression like 1/2x is interpreted as 1/(2x) by TI-82, but as (1/2)x by TI-83. While the first interpretation may be expected by some users, only the latter is in agreement with the standard rules stated above.

1/2x = 1/(2x) ¬O¹H¤Ï¼Ð·Ç©w¸qªº¡C
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12¡Ò(4+2)=????
=12¡Ò(4+2)
=12¡Ò2(1+2)
=(12¡Ò2)*(1¡Ò3)
=2<-------------
------------
30¡Ò(4+6)=????
=30¡Ò2(2+3)
=(30¡Ò2)*(1¡Ò5)
=3<-------------
------------
2(2+3)=10, µ¥©ó¡]4+6¡^=10, ©Î±N2´£¥X¬A¸¹¥~.
2a=2*a=10¡A­È·íµM¬Ûµ¥¡A¥i¬O¦b¹Bºâ¦¡¤¤¡A2(2+3)³Q¸É¤@­Ó*ÁÙ·|¬Ûµ¥¶Ü¡H¡A2(2+3)=10³Q§_©w¤F¡C
30¡Ò2(2+3)Åܦ¨(30¡Ò2)*(2+3)
-------------------------------
30¡Ò2(2+3)
=(30¡Ò2)*(2+3)
=15*(2+3)...###
----------------------
30¡Ò2(2+3)
=30¡Ò(1+1)(2+3)
=30¡Ò(2)(2+3)
=30¡Ò(4+6)
=30¡Ò2(2+3)...###¡]»P­pºâ¥Ñ¥ª¦Ó¥k§¹¥þ¤£½Ä¬ð¡^

°²³]a=2+3

30¡Ò2a
=30¡Ò(2a)
=30¡Ò2(2+3)
=30¡Ò(2*5)
=30¡Ò10
=3

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30¡Ò2a
=(30¡Ò2)*¡]2+3¡^
=15*5
=75
§_©w¤F2(2+3)=10