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¥[¤J¤é´Á: Dec 2006
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Basic Member
¥[¤J¤é´Á: Feb 2002 ±zªº¦í§}: ¦a²y
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®¤§Ú¤£«È®ðªºÁ¿ Ãø©Ç±z·d¤£²M·¡ Fourier "¨º§Ú¤]¥i¥H»¡1+£[¡A¦]¬°£[¹Gªñ0¡A©Ò¥H1=1+£[¡A³o¼Ë¯¸ªº¦í¸}¶Ü¡H" ±z¥ý¦^¥h¬Ý¬Ý·¥ªº©w¸q¡A¬Ý¬Ý¤H®a«ç»ò¸Ñ¨M³oÓ°ÝÃD¡C ¦A¨Ó§A°Ý¦Û¤v¤@Ó°ÝÃD¡G §A¦b°µÂà´«®É¡A¥kÃä¨ì©³n®i¶}¨ì²Ä´X¶µ¡Aµ¥¸¹¨âÃä¤~·|ÄY®æ¬Ûµ¥ ¡H §Ú¦Û¥H¬°¡A·í§A¦b°µ Fouries transformation ®É¡A¨ºÓ¸}´N¦Û¤v¸ó¤W¥h¤F¡C §Ú³o¼ËÁ¿±zÅ¥ªºÀ´¶Ü ¡H ¦^¨ì¥¿ÃD¡A¬O§_¥i¥H½Ð±z¦^ÀY¥h½½±zªº®Ñ¡A ¥ý¬Ý¬Ý®Ñ¤Wªº Transformation ¥Îªº¬O 1/2pi ÁÙ¬O 1/sqrt(2pi)¡A«eªÌªº¸Ü¡A¦A¬Ý¬ÝÃþ¦üªººâ¦¡¦b®Ñ¤¤¡A¥Î1/2piªº¼gªkÁÙ¬O 1/(2pi). ³o¤~¬O«ÂI¡C |
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Regular Member
![]() ![]() ¥[¤J¤é´Á: Jan 2005
¤å³¹: 72
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1¡Ò2=1/2¨S¿ù§a? 1x2=1(2)¨S¿ù§a? §Aªº¦M¾÷¸Ì¦³¼g¨ì³o¨Ç¡A ¦]¦¹1¡Ò2x¥i¥H¼g¦¨1/2x¨S°ÝÃD§a? ´«¦¨¤â¼g¤¤ªº²ßºD 1 -- 2x ³o»ò°µ¬O¬°¤F¹ê²{"µ²ºc"¦Ó¦s¦bªº¡A ¨Ã¤£¬O¥´¦L¤è«K¡A¤]¤£¬OÃi±o¼g²Å¸¹¡A ·íµM¬°¤°»òn¹ê²{µ²ºc¨º¬O¥t¥~¤@Ó°ÝÃD¤F¡A ¤Þ¥Î¦M¾÷ ¥|«h¹Bºâ¡]Four Arithmetic Operations¡^¡A§Y¥[´î¼°£¡A¬O¼Æ¾Ç³Ì°ò¥»ªº¹Bºâ¡C¦pªG¥[´î¼°£©ñ¦b¦P¤@Ӻ⦡¦C¤¤ªº¸Ü¡A¨äpºâªº¶¶§Ç¬O¡A¥ý¼°£¡A«á¥[´î¡A¬A¸¹¥ýºâ¡C¥|«h¹Bºâªº°_·½«Ü¦¡A´X¥G¦b¼Æ¾Ç²£¥Í®É´N¦³¤F¡C ¥|«h¹Bºâ³W«h ¤@¯ë¦Ó¨¥¡A¥Ñ¥ª¦Ó¥kºâ¡C ¥ý¡Ñ¡Ò «á+−¡]¥ý¼°£«á¥[´î¡^¡C ¦³(¬A¸¹)¥ýºâ¡C ¥ýºâ¤p¬A¸¹¡A¦Aºâ¤¤¬A¸¹¡A³Ì«áºâ¤j¬A¸¹¡C ª`·N¨ì¤F¶Ü?³o¸Ì¨Ã¨S¦³©w¸q2xa=2a, 30¡Ò2(2+3)¡Ò5¦b¥|«h¹Bºâ¸Ì¦³·N¸q¶Ü? ¦pªG¦³·N¸qªº¸Ü¡A¬°¤°»ò·|¥X²{2a? °ò©ó¬Æ»ò²z¥Ñ?©Àªk¬O?
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New Member
¥[¤J¤é´Á: Oct 2008
¤å³¹: 5
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¤§«e¦³¤H¶Kwiki
http://en.wikipedia.org/wiki/Order_of_operations ùر¦³¼g¨ì Similarly, care must be exercised when using the slash ('/') symbol. The string of characters "1/2x" is interpreted by the above conventions as (1/2)x. The contrary interpretation should be written explicitly as 1/(2x). Again, the use of brackets will clarify the meaning and should be used if there is any chance of misinterpretation. §Ú·Q³o¤]¬O¬°¦ócasio & TI ·|§â쥻ªº1/2Xµ¥©ó1/(2X)קאּ1/2Xµ¥©ó(1/2)Xªºì¦]§a?À³¸Ó´N¬O³oºØ°ÝÃD³y¦¨¤Ó¦h¤H§xÂZ¤F! §Ú¤â¤W¨S¼Æ¾Ç®Ñ¥i¥H¬d,¤£¹LGOOGLE 1/2X, SIN(1/2X), 1/2PI¤§Ãþªº¤èµ{¦¡...À³¸Óº¡¦hÃþ¦ü°ÝÃDªº! ¦¹¤å³¹©ó 2011-04-15 04:58 PM ³Q lowyield ½s¿è. |
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Regular Member
![]() ![]() ¥[¤J¤é´Á: Jan 2005
¤å³¹: 72
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30¡Ò2(x+3)¡Ò5=0.6 30¡Ò2(x+3)=0.6x5 30¡Ò2(x+3)=3 2(x+3)=30¡Ò3 2(x+3)=10 x+3=10¡Ò2 x+3=5 x=5-3 x=2 30¡Ò2(x+3)¡Ò5=0.6 30¡Ò2(x+3)=0.6x5 30¡Ò2(x+3)=3 30¡Ò(x+3)=3x2 30¡Ò(x+3)=6 x+3=30¡Ò6 x+3=5 x=5-3 x=2
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*°±Åv¤¤*
¥[¤J¤é´Á: Aug 2002
¤å³¹: 393
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ìÃD³æ¯Â´N¬O¾ã¼Æªº¥|«h¹Bºâ. ¦n,¸Õ°Ý¤@¤U 123+456=579 ¥i¥Hµw¸ÑÄÀ¦¨ 123+456 =6+120 =126 ¶Ü? «Ü¥i¯º§a «e±«ù2(2+3)À³¸Óµø¬°¤@¼Æ(©Î¤@Åé)ªº¤H,§A̤j·§¤]·|ı±o§Ú©ÒÁ|ªº¨ÒÃD,µª®×¬O126¤]¥i¥H§a?! «e±¦³¤@¦ì¥ý¶i»¡ªº¦n,¨Ò¦p:2Y, Y¬°¥¼ª¾¼Æ, 2¥iµø¬°Yªº«Y¼Æ. 2Y¤~¥i·í¦¨¤@Ó¼Æ. ¦ýìÃD¥u¬O³æ¯Âªº¾ã¼Æªº¥|«h¹Bºâ »¡·Ç½TÂI, ìÃD¥u¬O¤@Ó¼g¿ùÃD¥Øªº¾ã¼Æ¥|«h¹Bºâ, 2(2+3),2©M(¤§¶¡¤Ö¼g¤F¤@Ó¼¸¹. Y쥻¦³¥[¼¸¹,ºâªk«h¬O¥Ñ¥ª¨ì¥k¨Ì§Çºâ. ´N³o¼Ë,ÁÙ¦³¤°»ò¦n°Q½×ªº¶Ü. ¦¹¤å³¹©ó 2011-04-15 05:31 PM ³Q jshj0314 ½s¿è. |
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Silent Member
¥[¤J¤é´Á: Jan 2008
¤å³¹: 0
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¤Þ¥Î:
2x=2¡Dx=2(x) 1¡Ò2x=1¡Ò2(x)=1¡Ò2¡Dx=(1/2)x ©Ò¥HÁÙ¬O¦³°ÝÃD, °ÝÃD¦b 2x = (2x) ÁÙ¬O 2(x) ¤Þ¥Î:
¦ý 2a ¤@©wµ¥©ó 2xa ©Ò¥H 30¡Ò2x(2+3)¡Ò5 ¤@©w¬O¦¨¥ßªº |
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Regular Member
![]() ![]() ¥[¤J¤é´Á: Jan 2005
¤å³¹: 72
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2(2+3)ªºì«¬¬O?2x(2+3),2+3¬O¾ã¼Æ¶Ü? ÅãµM¤£¬O.... 2x(2+3) 2¬O³Q¼¼Æ(multiplicand ) 30¡Ò2x(2+3),°£¸¹(Rahn's notation)«áªº2Åܦ¨¤F°£¼Æ(divisor), ¨S·Q¨ì³æ¯Âªº¾ã¼Æªº¥|«h¹Bºâ¡A§Ú©~µMºâ¤£¥X15ªºµª®×¡A ¤£¹L½Ð©ñ¤ß¡A§Ú¨M©w«Åª°ê¤¤¤pªº¼Æ¾Ç½Ò¥»¡A ¤E¦~«á§Ú·|¨Ó¦^µª³o°ÝÃD¡A½Ð@¤ßµ¥«Ý
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Regular Member
![]() ![]() ¥[¤J¤é´Á: Jan 2005
¤å³¹: 72
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¤Þ¥Î:
2x = (2x) ÁÙ¬O 2(x) x=1 2x=2 (2x)=2 2(x)=2 2x=2¡Dx=2(x) x=1 2x=2 2¡Dx=2 2(x)=2 1¡Ò2x=1¡Ò2(x)=1¡Ò2¡Dx=(1/2)x x=1 1¡Ò2x=0.5 1¡Ò2(x)=0.5 1¡Ò2¡Dx=0.5 (1/2)x=0.5 x=2 1¡Ò2x¡Ò2=0.125 1¡Ò2*x¡Ò2=0.25 ¬°¤°»ò.........
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