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Major Member
 加入日期: Sep 2002
文章: 155
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2樓的0.5 / (x - a) - 0.5 / (x + a)反算回去會等於
a/(x^2-a^2) 不是a / ((x^2) - a) |
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2007-06-17, 08:13 PM
#11
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*停權中*
加入日期: Jul 2003 您的住址: 送八力的弟子, 恕我不屑回應你的發言
文章: 2,107
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我的答案是1/2(X*X-a)+a/2*ln(X*X-a)+C C為constant..
應該沒錯  |
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2007-06-17, 08:19 PM
#12
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New Member
加入日期: Apr 2007
文章: 2
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引用:
那就修正成0.5 / (x - (a^(1/2) ) - 0.5 / (x + a^(1/2)) |
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2007-06-17, 08:20 PM
#13
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Basic Member
加入日期: Dec 2004
文章: 25
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引用:
抱歉忘了檢查 (x^2) / ((x^2) - a) = ((x^2) - a) / ((x^2) - a) + a / ((x^2) - a) = 1 + 0.5 * (a^0.5) / (x - (a^0.5)) - 0.5 * (a^0.5) / (x + (a^0.5)) |
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2007-06-17, 08:28 PM
#14
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*停權中*
加入日期: Sep 2006
文章: 87
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引用:
=1+0.5*a^0.5(1/(x - (a^0.5))-1/(x + (a^0.5))) integral =x+0.5*a^0.5(ln|x-(a^0.5)|-ln|x+(a^0.5)|)+C =x+0.5*a^0.5ln|(x-(a^0.5))/(x+(a^0.5))|+C  |
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2007-06-17, 08:40 PM
#15
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Major Member
加入日期: Dec 2005
文章: 116
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抱歉
已確定 我的答案是錯的 |
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2007-06-17, 09:03 PM
#16
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*停權中*
加入日期: Jul 2003 您的住址: 送八力的弟子, 恕我不屑回應你的發言
文章: 2,107
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請樓主公布答案吧....
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2007-06-17, 09:40 PM
#17
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