https://www.felixcloutier.com/x86/andn

解說有點看不懂

範例 opcode:


Performs a bitwise logical AND of inverted second operand (the first source operand) with the third operand (the second source operand). The result is stored in the first operand (destination operand).


Operand 1 mod.reg eax
Operand 2 vex.vvvv ecx
Operand 3 mod.r/m edx

到底是 Operand 1 = Operand 3 & Operand 2
還是 Operand 1 = Operand 2 & Operand 3