PCDVD數位科技討論區 - 瀏覽單個文章

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mayuka

Master Member

加入日期: Oct 2004

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引用:

作者totorochen

Z=X+(X-Y)/(Y-1)+1
Z=最多可吃到幾個糖果
X=原始可購買到糖果的顆數
Y=每Y個糖果衣(包裝)可換一個糖果

Z=X+(X-Y)/(Y-1)+1───＞
Z＝X+(X-Y)/(Y-1)＋(Y-1)/ (Y-1)＝X+(X-1)/(Y-1)＝(XY-X)/(Y-1)＋(X-1)/(Y-1)＝(XY-1)/(Y-1)
？？？？

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2007-05-19, 06:30 AM #10