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doberman
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加入日期: Mar 2004
文章: 477
ye.. maybe should write the "Chain Rule":

dy/dx =dy/du * du/dx

in this case ln(1-x):
y=ln(1-x)
u=1-x

dy/du=d (lnu)/du=1/u
du/dx=-1
=>
dy/dx = dy/du * du/dx = 1/u * (-1) = -1/(1-x)
舊 2005-03-06, 01:07 AM #8
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